Metamath Proof Explorer


Theorem abex

Description: Conditions for a class abstraction to be a set. Remark: This proof is shorter than a proof using abexd . (Contributed by AV, 19-Apr-2025)

Ref Expression
Hypotheses abex.1 ( 𝜑𝑥𝐴 )
abex.2 𝐴 ∈ V
Assertion abex { 𝑥𝜑 } ∈ V

Proof

Step Hyp Ref Expression
1 abex.1 ( 𝜑𝑥𝐴 )
2 abex.2 𝐴 ∈ V
3 abss ( { 𝑥𝜑 } ⊆ 𝐴 ↔ ∀ 𝑥 ( 𝜑𝑥𝐴 ) )
4 3 1 mpgbir { 𝑥𝜑 } ⊆ 𝐴
5 2 4 ssexi { 𝑥𝜑 } ∈ V