Metamath Proof Explorer


Theorem abid2f

Description: A simplification of class abstraction. Theorem 5.2 of Quine p. 35. (Contributed by NM, 5-Sep-2011) (Revised by Mario Carneiro, 7-Oct-2016) (Proof shortened by Wolf Lammen, 26-Feb-2025)

Ref Expression
Hypothesis abid2f.1 𝑥 𝐴
Assertion abid2f { 𝑥𝑥𝐴 } = 𝐴

Proof

Step Hyp Ref Expression
1 abid2f.1 𝑥 𝐴
2 1 eqabf ( 𝐴 = { 𝑥𝑥𝐴 } ↔ ∀ 𝑥 ( 𝑥𝐴𝑥𝐴 ) )
3 biid ( 𝑥𝐴𝑥𝐴 )
4 2 3 mpgbir 𝐴 = { 𝑥𝑥𝐴 }
5 4 eqcomi { 𝑥𝑥𝐴 } = 𝐴