Metamath Proof Explorer
Description: Inference of abstraction subclass from implication. (Contributed by NM, 20-Jan-2006)
|
|
Ref |
Expression |
|
Hypothesis |
abssi.1 |
⊢ ( 𝜑 → 𝑥 ∈ 𝐴 ) |
|
Assertion |
abssi |
⊢ { 𝑥 ∣ 𝜑 } ⊆ 𝐴 |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
abssi.1 |
⊢ ( 𝜑 → 𝑥 ∈ 𝐴 ) |
| 2 |
1
|
ss2abi |
⊢ { 𝑥 ∣ 𝜑 } ⊆ { 𝑥 ∣ 𝑥 ∈ 𝐴 } |
| 3 |
|
abid2 |
⊢ { 𝑥 ∣ 𝑥 ∈ 𝐴 } = 𝐴 |
| 4 |
2 3
|
sseqtri |
⊢ { 𝑥 ∣ 𝜑 } ⊆ 𝐴 |