Metamath Proof Explorer


Theorem absval2d

Description: Value of absolute value function. Definition 10.36 of Gleason p. 133. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypothesis abscld.1 ( 𝜑𝐴 ∈ ℂ )
Assertion absval2d ( 𝜑 → ( abs ‘ 𝐴 ) = ( √ ‘ ( ( ( ℜ ‘ 𝐴 ) ↑ 2 ) + ( ( ℑ ‘ 𝐴 ) ↑ 2 ) ) ) )

Proof

Step Hyp Ref Expression
1 abscld.1 ( 𝜑𝐴 ∈ ℂ )
2 absval2 ( 𝐴 ∈ ℂ → ( abs ‘ 𝐴 ) = ( √ ‘ ( ( ( ℜ ‘ 𝐴 ) ↑ 2 ) + ( ( ℑ ‘ 𝐴 ) ↑ 2 ) ) ) )
3 1 2 syl ( 𝜑 → ( abs ‘ 𝐴 ) = ( √ ‘ ( ( ( ℜ ‘ 𝐴 ) ↑ 2 ) + ( ( ℑ ‘ 𝐴 ) ↑ 2 ) ) ) )