Metamath Proof Explorer


Theorem acsfn0

Description: Algebraicity of a point closure condition. (Contributed by Stefan O'Rear, 3-Apr-2015)

Ref Expression
Assertion acsfn0 ( ( 𝑋 ∈ 𝑉 ∧ 𝐾 ∈ 𝑋 ) → { 𝑎 ∈ 𝒫 𝑋 ∣ 𝐾 ∈ 𝑎 } ∈ ( ACS ‘ 𝑋 ) )

Proof

Step Hyp Ref Expression
1 0ss ⊢ ∅ ⊆ 𝑎
2 1 a1bi ⊢ ( 𝐾 ∈ 𝑎 ↔ ( ∅ ⊆ 𝑎 → 𝐾 ∈ 𝑎 ) )
3 2 rabbii ⊢ { 𝑎 ∈ 𝒫 𝑋 ∣ 𝐾 ∈ 𝑎 } = { 𝑎 ∈ 𝒫 𝑋 ∣ ( ∅ ⊆ 𝑎 → 𝐾 ∈ 𝑎 ) }
4 0ss ⊢ ∅ ⊆ 𝑋
5 0fi ⊢ ∅ ∈ Fin
6 acsfn ⊢ ( ( ( 𝑋 ∈ 𝑉 ∧ 𝐾 ∈ 𝑋 ) ∧ ( ∅ ⊆ 𝑋 ∧ ∅ ∈ Fin ) ) → { 𝑎 ∈ 𝒫 𝑋 ∣ ( ∅ ⊆ 𝑎 → 𝐾 ∈ 𝑎 ) } ∈ ( ACS ‘ 𝑋 ) )
7 4 5 6 mpanr12 ⊢ ( ( 𝑋 ∈ 𝑉 ∧ 𝐾 ∈ 𝑋 ) → { 𝑎 ∈ 𝒫 𝑋 ∣ ( ∅ ⊆ 𝑎 → 𝐾 ∈ 𝑎 ) } ∈ ( ACS ‘ 𝑋 ) )
8 3 7 eqeltrid ⊢ ( ( 𝑋 ∈ 𝑉 ∧ 𝐾 ∈ 𝑋 ) → { 𝑎 ∈ 𝒫 𝑋 ∣ 𝐾 ∈ 𝑎 } ∈ ( ACS ‘ 𝑋 ) )