Metamath Proof Explorer


Theorem ad5ant25

Description: Deduction adding conjuncts to antecedent. (Contributed by Alan Sare, 17-Oct-2017) (Proof shortened by Wolf Lammen, 14-Apr-2022)

Ref Expression
Hypothesis ad5ant2.1 ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 )
Assertion ad5ant25 ( ( ( ( ( 𝜃 ∧ 𝜑 ) ∧ 𝜏 ) ∧ 𝜂 ) ∧ 𝜓 ) → 𝜒 )

Proof

Step Hyp Ref Expression
1 ad5ant2.1 ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 )
2 1 adantll ⊢ ( ( ( 𝜃 ∧ 𝜑 ) ∧ 𝜓 ) → 𝜒 )
3 2 ad4ant14 ⊢ ( ( ( ( ( 𝜃 ∧ 𝜑 ) ∧ 𝜏 ) ∧ 𝜂 ) ∧ 𝜓 ) → 𝜒 )