| Step | Hyp | Ref | Expression | 
						
							| 1 |  | addcom | ⊢ ( ( 𝐴  ∈  ℂ  ∧  𝐵  ∈  ℂ )  →  ( 𝐴  +  𝐵 )  =  ( 𝐵  +  𝐴 ) ) | 
						
							| 2 | 1 | oveq1d | ⊢ ( ( 𝐴  ∈  ℂ  ∧  𝐵  ∈  ℂ )  →  ( ( 𝐴  +  𝐵 )  +  𝐶 )  =  ( ( 𝐵  +  𝐴 )  +  𝐶 ) ) | 
						
							| 3 | 2 | 3adant3 | ⊢ ( ( 𝐴  ∈  ℂ  ∧  𝐵  ∈  ℂ  ∧  𝐶  ∈  ℂ )  →  ( ( 𝐴  +  𝐵 )  +  𝐶 )  =  ( ( 𝐵  +  𝐴 )  +  𝐶 ) ) | 
						
							| 4 |  | addass | ⊢ ( ( 𝐴  ∈  ℂ  ∧  𝐵  ∈  ℂ  ∧  𝐶  ∈  ℂ )  →  ( ( 𝐴  +  𝐵 )  +  𝐶 )  =  ( 𝐴  +  ( 𝐵  +  𝐶 ) ) ) | 
						
							| 5 |  | addass | ⊢ ( ( 𝐵  ∈  ℂ  ∧  𝐴  ∈  ℂ  ∧  𝐶  ∈  ℂ )  →  ( ( 𝐵  +  𝐴 )  +  𝐶 )  =  ( 𝐵  +  ( 𝐴  +  𝐶 ) ) ) | 
						
							| 6 | 5 | 3com12 | ⊢ ( ( 𝐴  ∈  ℂ  ∧  𝐵  ∈  ℂ  ∧  𝐶  ∈  ℂ )  →  ( ( 𝐵  +  𝐴 )  +  𝐶 )  =  ( 𝐵  +  ( 𝐴  +  𝐶 ) ) ) | 
						
							| 7 | 3 4 6 | 3eqtr3d | ⊢ ( ( 𝐴  ∈  ℂ  ∧  𝐵  ∈  ℂ  ∧  𝐶  ∈  ℂ )  →  ( 𝐴  +  ( 𝐵  +  𝐶 ) )  =  ( 𝐵  +  ( 𝐴  +  𝐶 ) ) ) |