Metamath Proof Explorer


Theorem addcuts2

Description: Show that the cut involved in surreal addition is legitimate. (Contributed by Scott Fenton, 8-Mar-2025)

Ref Expression
Hypotheses addcuts.1 ⊢ ( 𝜑 → 𝑋 ∈ No )
addcuts.2 ⊢ ( 𝜑 → 𝑌 ∈ No )
Assertion addcuts2 ( 𝜑 → ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) )

Proof

Step Hyp Ref Expression
1 addcuts.1 ⊢ ( 𝜑 → 𝑋 ∈ No )
2 addcuts.2 ⊢ ( 𝜑 → 𝑌 ∈ No )
3 1 2 addcuts ⊢ ( 𝜑 → ( ( 𝑋 +s 𝑌 ) ∈ No ∧ ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s { ( 𝑋 +s 𝑌 ) } ∧ { ( 𝑋 +s 𝑌 ) } <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) ) )
4 3anass ⊢ ( ( ( 𝑋 +s 𝑌 ) ∈ No ∧ ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s { ( 𝑋 +s 𝑌 ) } ∧ { ( 𝑋 +s 𝑌 ) } <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) ) ↔ ( ( 𝑋 +s 𝑌 ) ∈ No ∧ ( ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s { ( 𝑋 +s 𝑌 ) } ∧ { ( 𝑋 +s 𝑌 ) } <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) ) ) )
5 3 4 sylib ⊢ ( 𝜑 → ( ( 𝑋 +s 𝑌 ) ∈ No ∧ ( ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s { ( 𝑋 +s 𝑌 ) } ∧ { ( 𝑋 +s 𝑌 ) } <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) ) ) )
6 5 simprd ⊢ ( 𝜑 → ( ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s { ( 𝑋 +s 𝑌 ) } ∧ { ( 𝑋 +s 𝑌 ) } <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) ) )
7 ovex ⊢ ( 𝑋 +s 𝑌 ) ∈ V
8 7 snnz ⊢ { ( 𝑋 +s 𝑌 ) } ≠ ∅
9 sltstr ⊢ ( ( ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s { ( 𝑋 +s 𝑌 ) } ∧ { ( 𝑋 +s 𝑌 ) } <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) ∧ { ( 𝑋 +s 𝑌 ) } ≠ ∅ ) → ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) )
10 8 9 mp3an3 ⊢ ( ( ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s { ( 𝑋 +s 𝑌 ) } ∧ { ( 𝑋 +s 𝑌 ) } <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) ) → ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) )
11 6 10 syl ⊢ ( 𝜑 → ( { 𝑝 ∣ ∃ 𝑙 ∈ ( L ‘ 𝑋 ) 𝑝 = ( 𝑙 +s 𝑌 ) } ∪ { 𝑞 ∣ ∃ 𝑚 ∈ ( L ‘ 𝑌 ) 𝑞 = ( 𝑋 +s 𝑚 ) } ) <<s ( { 𝑤 ∣ ∃ 𝑟 ∈ ( R ‘ 𝑋 ) 𝑤 = ( 𝑟 +s 𝑌 ) } ∪ { 𝑡 ∣ ∃ 𝑠 ∈ ( R ‘ 𝑌 ) 𝑡 = ( 𝑋 +s 𝑠 ) } ) )