Metamath Proof Explorer


Theorem adjsslnop

Description: Every operator with an adjoint is linear. (Contributed by NM, 17-Jun-2006) (New usage is discouraged.)

Ref Expression
Assertion adjsslnop dom adjℎ ⊆ LinOp

Proof

Step Hyp Ref Expression
1 adjadj ⊢ ( 𝑡 ∈ dom adjℎ → ( adjℎ ‘ ( adjℎ ‘ 𝑡 ) ) = 𝑡 )
2 dmadjrn ⊢ ( 𝑡 ∈ dom adjℎ → ( adjℎ ‘ 𝑡 ) ∈ dom adjℎ )
3 adjlnop ⊢ ( ( adjℎ ‘ 𝑡 ) ∈ dom adjℎ → ( adjℎ ‘ ( adjℎ ‘ 𝑡 ) ) ∈ LinOp )
4 2 3 syl ⊢ ( 𝑡 ∈ dom adjℎ → ( adjℎ ‘ ( adjℎ ‘ 𝑡 ) ) ∈ LinOp )
5 1 4 eqeltrrd ⊢ ( 𝑡 ∈ dom adjℎ → 𝑡 ∈ LinOp )
6 5 ssriv ⊢ dom adjℎ ⊆ LinOp