Metamath Proof Explorer


Theorem aevlem0

Description: Lemma for aevlem . Instance of aev . (Contributed by NM, 8-Jul-2016) (Proof shortened by Wolf Lammen, 17-Feb-2018) Remove dependency on ax-12 . (Revised by Wolf Lammen, 14-Mar-2021) (Revised by BJ, 29-Mar-2021) (Proof shortened by Wolf Lammen, 30-Mar-2021)

Ref Expression
Assertion aevlem0 ( ∀ 𝑥 𝑥 = 𝑦 → ∀ 𝑧 𝑧 = 𝑥 )

Proof

Step Hyp Ref Expression
1 spaev ( ∀ 𝑥 𝑥 = 𝑦𝑥 = 𝑦 )
2 1 alrimiv ( ∀ 𝑥 𝑥 = 𝑦 → ∀ 𝑧 𝑥 = 𝑦 )
3 cbvaev ( ∀ 𝑥 𝑥 = 𝑦 → ∀ 𝑧 𝑧 = 𝑦 )
4 equeuclr ( 𝑥 = 𝑦 → ( 𝑧 = 𝑦𝑧 = 𝑥 ) )
5 4 al2imi ( ∀ 𝑧 𝑥 = 𝑦 → ( ∀ 𝑧 𝑧 = 𝑦 → ∀ 𝑧 𝑧 = 𝑥 ) )
6 2 3 5 sylc ( ∀ 𝑥 𝑥 = 𝑦 → ∀ 𝑧 𝑧 = 𝑥 )