Metamath Proof Explorer
Description: Conjoin antecedents and consequents in a deduction. (Contributed by NM, 3-Apr-1994) (Proof shortened by Wolf Lammen, 18-Dec-2013)
|
|
Ref |
Expression |
|
Hypotheses |
anim12d.1 |
⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) ) |
|
|
anim12d.2 |
⊢ ( 𝜑 → ( 𝜃 → 𝜏 ) ) |
|
Assertion |
anim12d |
⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜃 ) → ( 𝜒 ∧ 𝜏 ) ) ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
anim12d.1 |
⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) ) |
| 2 |
|
anim12d.2 |
⊢ ( 𝜑 → ( 𝜃 → 𝜏 ) ) |
| 3 |
|
idd |
⊢ ( 𝜑 → ( ( 𝜒 ∧ 𝜏 ) → ( 𝜒 ∧ 𝜏 ) ) ) |
| 4 |
1 2 3
|
syl2and |
⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜃 ) → ( 𝜒 ∧ 𝜏 ) ) ) |