Metamath Proof Explorer
Description: Conjoin antecedents and consequents in a deduction. (Contributed by Jeff Madsen, 16-Jun-2011)
|
|
Ref |
Expression |
|
Hypotheses |
anim12dan.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 ) |
|
|
anim12dan.2 |
⊢ ( ( 𝜑 ∧ 𝜃 ) → 𝜏 ) |
|
Assertion |
anim12dan |
⊢ ( ( 𝜑 ∧ ( 𝜓 ∧ 𝜃 ) ) → ( 𝜒 ∧ 𝜏 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
anim12dan.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜒 ) |
2 |
|
anim12dan.2 |
⊢ ( ( 𝜑 ∧ 𝜃 ) → 𝜏 ) |
3 |
1
|
ex |
⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) ) |
4 |
2
|
ex |
⊢ ( 𝜑 → ( 𝜃 → 𝜏 ) ) |
5 |
3 4
|
anim12d |
⊢ ( 𝜑 → ( ( 𝜓 ∧ 𝜃 ) → ( 𝜒 ∧ 𝜏 ) ) ) |
6 |
5
|
imp |
⊢ ( ( 𝜑 ∧ ( 𝜓 ∧ 𝜃 ) ) → ( 𝜒 ∧ 𝜏 ) ) |