Description: Conjunction implies disjunction with one common formula (4/4). (Contributed by BJ, 4-Oct-2019)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | animorrl | ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜓 ∨ 𝜒 ) ) | 
| Step | Hyp | Ref | Expression | 
|---|---|---|---|
| 1 | simpr | ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜓 ) | |
| 2 | 1 | orcd | ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜓 ∨ 𝜒 ) ) |