Metamath Proof Explorer


Theorem asclrhm

Description: The scalar injection is a ring homomorphism. (Contributed by Mario Carneiro, 8-Mar-2015)

Ref Expression
Hypotheses asclrhm.a 𝐴 = ( algSc ‘ 𝑊 )
asclrhm.f 𝐹 = ( Scalar ‘ 𝑊 )
Assertion asclrhm ( 𝑊 ∈ AssAlg → 𝐴 ∈ ( 𝐹 RingHom 𝑊 ) )

Proof

Step Hyp Ref Expression
1 asclrhm.a 𝐴 = ( algSc ‘ 𝑊 )
2 asclrhm.f 𝐹 = ( Scalar ‘ 𝑊 )
3 eqid ( Base ‘ 𝐹 ) = ( Base ‘ 𝐹 )
4 eqid ( 1r𝐹 ) = ( 1r𝐹 )
5 eqid ( 1r𝑊 ) = ( 1r𝑊 )
6 eqid ( .r𝐹 ) = ( .r𝐹 )
7 eqid ( .r𝑊 ) = ( .r𝑊 )
8 2 assasca ( 𝑊 ∈ AssAlg → 𝐹 ∈ Ring )
9 assaring ( 𝑊 ∈ AssAlg → 𝑊 ∈ Ring )
10 assalmod ( 𝑊 ∈ AssAlg → 𝑊 ∈ LMod )
11 1 2 10 9 ascl1 ( 𝑊 ∈ AssAlg → ( 𝐴 ‘ ( 1r𝐹 ) ) = ( 1r𝑊 ) )
12 1 2 3 7 6 ascldimul ( ( 𝑊 ∈ AssAlg ∧ 𝑥 ∈ ( Base ‘ 𝐹 ) ∧ 𝑦 ∈ ( Base ‘ 𝐹 ) ) → ( 𝐴 ‘ ( 𝑥 ( .r𝐹 ) 𝑦 ) ) = ( ( 𝐴𝑥 ) ( .r𝑊 ) ( 𝐴𝑦 ) ) )
13 12 3expb ( ( 𝑊 ∈ AssAlg ∧ ( 𝑥 ∈ ( Base ‘ 𝐹 ) ∧ 𝑦 ∈ ( Base ‘ 𝐹 ) ) ) → ( 𝐴 ‘ ( 𝑥 ( .r𝐹 ) 𝑦 ) ) = ( ( 𝐴𝑥 ) ( .r𝑊 ) ( 𝐴𝑦 ) ) )
14 1 2 9 10 asclghm ( 𝑊 ∈ AssAlg → 𝐴 ∈ ( 𝐹 GrpHom 𝑊 ) )
15 3 4 5 6 7 8 9 11 13 14 isrhm2d ( 𝑊 ∈ AssAlg → 𝐴 ∈ ( 𝐹 RingHom 𝑊 ) )