Metamath Proof Explorer


Theorem ax12f

Description: Basis step for constructing a substitution instance of ax-c15 without using ax-c15 . We can start with any formula ph in which x is not free. (Contributed by NM, 21-Jan-2007) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis ax12f.1 ( 𝜑 → ∀ 𝑥 𝜑 )
Assertion ax12f ( ¬ ∀ 𝑥 𝑥 = 𝑦 → ( 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) ) )

Proof

Step Hyp Ref Expression
1 ax12f.1 ( 𝜑 → ∀ 𝑥 𝜑 )
2 ax-1 ( 𝜑 → ( 𝑥 = 𝑦𝜑 ) )
3 1 2 alrimih ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
4 3 2a1i ( ¬ ∀ 𝑥 𝑥 = 𝑦 → ( 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) ) )