Description: Proof of ax-7 from ax7v1 and ax7v2 (and earlier axioms), proving sufficiency of the conjunction of the latter two weakened versions of ax7v , which is itself a weakened version of ax-7 .
Note that the weakened version of ax-7 obtained by adding a disjoint variable condition on x , z (resp. on y , z ) does not permit, together with the other axioms, to prove reflexivity (resp. symmetry). (Contributed by BJ, 7-Dec-2020)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | ax7 | ⊢ ( 𝑥 = 𝑦 → ( 𝑥 = 𝑧 → 𝑦 = 𝑧 ) ) | 
| Step | Hyp | Ref | Expression | 
|---|---|---|---|
| 1 | ax7v2 | ⊢ ( 𝑥 = 𝑡 → ( 𝑥 = 𝑦 → 𝑡 = 𝑦 ) ) | |
| 2 | ax7v2 | ⊢ ( 𝑥 = 𝑡 → ( 𝑥 = 𝑧 → 𝑡 = 𝑧 ) ) | |
| 3 | ax7v1 | ⊢ ( 𝑡 = 𝑦 → ( 𝑡 = 𝑧 → 𝑦 = 𝑧 ) ) | |
| 4 | 3 | imp | ⊢ ( ( 𝑡 = 𝑦 ∧ 𝑡 = 𝑧 ) → 𝑦 = 𝑧 ) | 
| 5 | 4 | a1i | ⊢ ( 𝑥 = 𝑡 → ( ( 𝑡 = 𝑦 ∧ 𝑡 = 𝑧 ) → 𝑦 = 𝑧 ) ) | 
| 6 | 1 2 5 | syl2and | ⊢ ( 𝑥 = 𝑡 → ( ( 𝑥 = 𝑦 ∧ 𝑥 = 𝑧 ) → 𝑦 = 𝑧 ) ) | 
| 7 | ax6evr | ⊢ ∃ 𝑡 𝑥 = 𝑡 | |
| 8 | 6 7 | exlimiiv | ⊢ ( ( 𝑥 = 𝑦 ∧ 𝑥 = 𝑧 ) → 𝑦 = 𝑧 ) | 
| 9 | 8 | ex | ⊢ ( 𝑥 = 𝑦 → ( 𝑥 = 𝑧 → 𝑦 = 𝑧 ) ) |