Metamath Proof Explorer


Theorem ax7v2

Description: Second of two weakened versions of ax7v , with an extra disjoint variable condition on y , z , see comments there. (Contributed by BJ, 7-Dec-2020)

Ref Expression
Assertion ax7v2 ( 𝑥 = 𝑦 → ( 𝑥 = 𝑧𝑦 = 𝑧 ) )

Proof

Step Hyp Ref Expression
1 ax7v ( 𝑥 = 𝑦 → ( 𝑥 = 𝑧𝑦 = 𝑧 ) )