Metamath Proof Explorer


Theorem axc16ALT

Description: Alternate proof of axc16 , shorter but requiring ax-10 , ax-11 , ax-13 and using df-nf and df-sb . (Contributed by NM, 17-May-2008) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion axc16ALT ( ∀ 𝑥 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑥 𝜑 ) )

Proof

Step Hyp Ref Expression
1 sbequ12 ( 𝑥 = 𝑧 → ( 𝜑 ↔ [ 𝑧 / 𝑥 ] 𝜑 ) )
2 ax-5 ( 𝜑 → ∀ 𝑧 𝜑 )
3 2 hbsb3 ( [ 𝑧 / 𝑥 ] 𝜑 → ∀ 𝑥 [ 𝑧 / 𝑥 ] 𝜑 )
4 1 3 axc16i ( ∀ 𝑥 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑥 𝜑 ) )