Metamath Proof Explorer


Theorem ballotleme

Description: Elements of E . (Contributed by Thierry Arnoux, 14-Dec-2016)

Ref Expression
Hypotheses ballotth.m ⊢ 𝑀 ∈ ℕ
ballotth.n ⊢ 𝑁 ∈ ℕ
ballotth.o ⊢ 𝑂 = { 𝑐 ∈ 𝒫 ( 1 ... ( 𝑀 + 𝑁 ) ) ∣ ( ♯ ‘ 𝑐 ) = 𝑀 }
ballotth.p ⊢ 𝑃 = ( 𝑥 ∈ 𝒫 𝑂 ↦ ( ( ♯ ‘ 𝑥 ) / ( ♯ ‘ 𝑂 ) ) )
ballotth.f ⊢ 𝐹 = ( 𝑐 ∈ 𝑂 ↦ ( 𝑖 ∈ ℤ ↦ ( ( ♯ ‘ ( ( 1 ... 𝑖 ) ∩ 𝑐 ) ) − ( ♯ ‘ ( ( 1 ... 𝑖 ) ∖ 𝑐 ) ) ) ) )
ballotth.e ⊢ 𝐸 = { 𝑐 ∈ 𝑂 ∣ ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝑐 ) ‘ 𝑖 ) }
Assertion ballotleme ( 𝐶 ∈ 𝐸 ↔ ( 𝐶 ∈ 𝑂 ∧ ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝐶 ) ‘ 𝑖 ) ) )

Proof

Step Hyp Ref Expression
1 ballotth.m ⊢ 𝑀 ∈ ℕ
2 ballotth.n ⊢ 𝑁 ∈ ℕ
3 ballotth.o ⊢ 𝑂 = { 𝑐 ∈ 𝒫 ( 1 ... ( 𝑀 + 𝑁 ) ) ∣ ( ♯ ‘ 𝑐 ) = 𝑀 }
4 ballotth.p ⊢ 𝑃 = ( 𝑥 ∈ 𝒫 𝑂 ↦ ( ( ♯ ‘ 𝑥 ) / ( ♯ ‘ 𝑂 ) ) )
5 ballotth.f ⊢ 𝐹 = ( 𝑐 ∈ 𝑂 ↦ ( 𝑖 ∈ ℤ ↦ ( ( ♯ ‘ ( ( 1 ... 𝑖 ) ∩ 𝑐 ) ) − ( ♯ ‘ ( ( 1 ... 𝑖 ) ∖ 𝑐 ) ) ) ) )
6 ballotth.e ⊢ 𝐸 = { 𝑐 ∈ 𝑂 ∣ ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝑐 ) ‘ 𝑖 ) }
7 fveq2 ⊢ ( 𝑑 = 𝐶 → ( 𝐹 ‘ 𝑑 ) = ( 𝐹 ‘ 𝐶 ) )
8 7 fveq1d ⊢ ( 𝑑 = 𝐶 → ( ( 𝐹 ‘ 𝑑 ) ‘ 𝑖 ) = ( ( 𝐹 ‘ 𝐶 ) ‘ 𝑖 ) )
9 8 breq2d ⊢ ( 𝑑 = 𝐶 → ( 0 < ( ( 𝐹 ‘ 𝑑 ) ‘ 𝑖 ) ↔ 0 < ( ( 𝐹 ‘ 𝐶 ) ‘ 𝑖 ) ) )
10 9 ralbidv ⊢ ( 𝑑 = 𝐶 → ( ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝑑 ) ‘ 𝑖 ) ↔ ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝐶 ) ‘ 𝑖 ) ) )
11 fveq2 ⊢ ( 𝑐 = 𝑑 → ( 𝐹 ‘ 𝑐 ) = ( 𝐹 ‘ 𝑑 ) )
12 11 fveq1d ⊢ ( 𝑐 = 𝑑 → ( ( 𝐹 ‘ 𝑐 ) ‘ 𝑖 ) = ( ( 𝐹 ‘ 𝑑 ) ‘ 𝑖 ) )
13 12 breq2d ⊢ ( 𝑐 = 𝑑 → ( 0 < ( ( 𝐹 ‘ 𝑐 ) ‘ 𝑖 ) ↔ 0 < ( ( 𝐹 ‘ 𝑑 ) ‘ 𝑖 ) ) )
14 13 ralbidv ⊢ ( 𝑐 = 𝑑 → ( ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝑐 ) ‘ 𝑖 ) ↔ ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝑑 ) ‘ 𝑖 ) ) )
15 14 cbvrabv ⊢ { 𝑐 ∈ 𝑂 ∣ ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝑐 ) ‘ 𝑖 ) } = { 𝑑 ∈ 𝑂 ∣ ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝑑 ) ‘ 𝑖 ) }
16 6 15 eqtri ⊢ 𝐸 = { 𝑑 ∈ 𝑂 ∣ ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝑑 ) ‘ 𝑖 ) }
17 10 16 elrab2 ⊢ ( 𝐶 ∈ 𝐸 ↔ ( 𝐶 ∈ 𝑂 ∧ ∀ 𝑖 ∈ ( 1 ... ( 𝑀 + 𝑁 ) ) 0 < ( ( 𝐹 ‘ 𝐶 ) ‘ 𝑖 ) ) )