Metamath Proof Explorer


Theorem biimprd

Description: Deduce a converse implication from a logical equivalence. Deduction associated with biimpr and biimpri . (Contributed by NM, 11-Jan-1993) (Proof shortened by Wolf Lammen, 22-Sep-2013)

Ref Expression
Hypothesis biimprd.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
Assertion biimprd ( 𝜑 → ( 𝜒 → 𝜓 ) )

Proof

Step Hyp Ref Expression
1 biimprd.1 ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) )
2 id ⊢ ( 𝜒 → 𝜒 )
3 2 1 imbitrrid ⊢ ( 𝜑 → ( 𝜒 → 𝜓 ) )