Metamath Proof Explorer


Theorem bj-2albi

Description: Closed form of 2albii . (Contributed by BJ, 6-May-2019)

Ref Expression
Assertion bj-2albi ( ∀ 𝑥 ∀ 𝑦 ( 𝜑 ↔ 𝜓 ) → ( ∀ 𝑥 ∀ 𝑦 𝜑 ↔ ∀ 𝑥 ∀ 𝑦 𝜓 ) )

Proof

Step Hyp Ref Expression
1 albi ⊢ ( ∀ 𝑦 ( 𝜑 ↔ 𝜓 ) → ( ∀ 𝑦 𝜑 ↔ ∀ 𝑦 𝜓 ) )
2 1 alimi ⊢ ( ∀ 𝑥 ∀ 𝑦 ( 𝜑 ↔ 𝜓 ) → ∀ 𝑥 ( ∀ 𝑦 𝜑 ↔ ∀ 𝑦 𝜓 ) )
3 albi ⊢ ( ∀ 𝑥 ( ∀ 𝑦 𝜑 ↔ ∀ 𝑦 𝜓 ) → ( ∀ 𝑥 ∀ 𝑦 𝜑 ↔ ∀ 𝑥 ∀ 𝑦 𝜓 ) )
4 2 3 syl ⊢ ( ∀ 𝑥 ∀ 𝑦 ( 𝜑 ↔ 𝜓 ) → ( ∀ 𝑥 ∀ 𝑦 𝜑 ↔ ∀ 𝑥 ∀ 𝑦 𝜓 ) )