Metamath Proof Explorer


Theorem bj-2exim

Description: Closed form of 2eximi . (Contributed by BJ, 6-May-2019)

Ref Expression
Assertion bj-2exim ( ∀ 𝑥 ∀ 𝑦 ( 𝜑 → 𝜓 ) → ( ∃ 𝑥 ∃ 𝑦 𝜑 → ∃ 𝑥 ∃ 𝑦 𝜓 ) )

Proof

Step Hyp Ref Expression
1 exim ⊢ ( ∀ 𝑦 ( 𝜑 → 𝜓 ) → ( ∃ 𝑦 𝜑 → ∃ 𝑦 𝜓 ) )
2 1 aleximi ⊢ ( ∀ 𝑥 ∀ 𝑦 ( 𝜑 → 𝜓 ) → ( ∃ 𝑥 ∃ 𝑦 𝜑 → ∃ 𝑥 ∃ 𝑦 𝜓 ) )