Metamath Proof Explorer


Theorem bj-ax12

Description: Remove a DV condition from bj-ax12v (using core axioms only). (Contributed by BJ, 26-Dec-2020) (Proof modification is discouraged.)

Ref Expression
Assertion bj-ax12 𝑥 ( 𝑥 = 𝑡 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑡𝜑 ) ) )

Proof

Step Hyp Ref Expression
1 bj-ax12v 𝑥 ( 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) )
2 equequ2 ( 𝑦 = 𝑡 → ( 𝑥 = 𝑦𝑥 = 𝑡 ) )
3 2 imbi1d ( 𝑦 = 𝑡 → ( ( 𝑥 = 𝑦𝜑 ) ↔ ( 𝑥 = 𝑡𝜑 ) ) )
4 3 albidv ( 𝑦 = 𝑡 → ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ ∀ 𝑥 ( 𝑥 = 𝑡𝜑 ) ) )
5 4 imbi2d ( 𝑦 = 𝑡 → ( ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) ↔ ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑡𝜑 ) ) ) )
6 2 5 imbi12d ( 𝑦 = 𝑡 → ( ( 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) ) ↔ ( 𝑥 = 𝑡 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑡𝜑 ) ) ) ) )
7 6 albidv ( 𝑦 = 𝑡 → ( ∀ 𝑥 ( 𝑥 = 𝑦 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ) ) ↔ ∀ 𝑥 ( 𝑥 = 𝑡 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑡𝜑 ) ) ) ) )
8 1 7 mpbii ( 𝑦 = 𝑡 → ∀ 𝑥 ( 𝑥 = 𝑡 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑡𝜑 ) ) ) )
9 ax6ev 𝑦 𝑦 = 𝑡
10 8 9 exlimiiv 𝑥 ( 𝑥 = 𝑡 → ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑡𝜑 ) ) )