Metamath Proof Explorer


Theorem bj-axc10v

Description: Version of axc10 with a disjoint variable condition, which does not require ax-13 . (Contributed by BJ, 14-Jun-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-axc10v ( ∀ 𝑥 ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → 𝜑 )

Proof

Step Hyp Ref Expression
1 ax6v ¬ ∀ 𝑥 ¬ 𝑥 = 𝑦
2 con3 ( ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → ( ¬ ∀ 𝑥 𝜑 → ¬ 𝑥 = 𝑦 ) )
3 2 al2imi ( ∀ 𝑥 ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → ( ∀ 𝑥 ¬ ∀ 𝑥 𝜑 → ∀ 𝑥 ¬ 𝑥 = 𝑦 ) )
4 1 3 mtoi ( ∀ 𝑥 ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑 )
5 axc7 ( ¬ ∀ 𝑥 ¬ ∀ 𝑥 𝜑𝜑 )
6 4 5 syl ( ∀ 𝑥 ( 𝑥 = 𝑦 → ∀ 𝑥 𝜑 ) → 𝜑 )