Description: Version of cbv1h with a disjoint variable condition, which does not require ax-13 . (Contributed by BJ, 16-Jun-2019) (Proof modification is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | bj-cbv1hv.1 | ⊢ ( 𝜑 → ( 𝜓 → ∀ 𝑦 𝜓 ) ) | |
| bj-cbv1hv.2 | ⊢ ( 𝜑 → ( 𝜒 → ∀ 𝑥 𝜒 ) ) | ||
| bj-cbv1hv.3 | ⊢ ( 𝜑 → ( 𝑥 = 𝑦 → ( 𝜓 → 𝜒 ) ) ) | ||
| Assertion | bj-cbv1hv | ⊢ ( ∀ 𝑥 ∀ 𝑦 𝜑 → ( ∀ 𝑥 𝜓 → ∀ 𝑦 𝜒 ) ) | 
| Step | Hyp | Ref | Expression | 
|---|---|---|---|
| 1 | bj-cbv1hv.1 | ⊢ ( 𝜑 → ( 𝜓 → ∀ 𝑦 𝜓 ) ) | |
| 2 | bj-cbv1hv.2 | ⊢ ( 𝜑 → ( 𝜒 → ∀ 𝑥 𝜒 ) ) | |
| 3 | bj-cbv1hv.3 | ⊢ ( 𝜑 → ( 𝑥 = 𝑦 → ( 𝜓 → 𝜒 ) ) ) | |
| 4 | nfa1 | ⊢ Ⅎ 𝑥 ∀ 𝑥 ∀ 𝑦 𝜑 | |
| 5 | nfa2 | ⊢ Ⅎ 𝑦 ∀ 𝑥 ∀ 𝑦 𝜑 | |
| 6 | 2sp | ⊢ ( ∀ 𝑥 ∀ 𝑦 𝜑 → 𝜑 ) | |
| 7 | 6 1 | syl | ⊢ ( ∀ 𝑥 ∀ 𝑦 𝜑 → ( 𝜓 → ∀ 𝑦 𝜓 ) ) | 
| 8 | 5 7 | nf5d | ⊢ ( ∀ 𝑥 ∀ 𝑦 𝜑 → Ⅎ 𝑦 𝜓 ) | 
| 9 | 6 2 | syl | ⊢ ( ∀ 𝑥 ∀ 𝑦 𝜑 → ( 𝜒 → ∀ 𝑥 𝜒 ) ) | 
| 10 | 4 9 | nf5d | ⊢ ( ∀ 𝑥 ∀ 𝑦 𝜑 → Ⅎ 𝑥 𝜒 ) | 
| 11 | 6 3 | syl | ⊢ ( ∀ 𝑥 ∀ 𝑦 𝜑 → ( 𝑥 = 𝑦 → ( 𝜓 → 𝜒 ) ) ) | 
| 12 | 4 5 8 10 11 | cbv1v | ⊢ ( ∀ 𝑥 ∀ 𝑦 𝜑 → ( ∀ 𝑥 𝜓 → ∀ 𝑦 𝜒 ) ) |