Metamath Proof Explorer


Theorem bj-hbs1

Description: Version of hbsb2 with a disjoint variable condition, which does not require ax-13 , and removal of ax-13 from hbs1 . (Contributed by BJ, 23-Jun-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-hbs1 ( [ 𝑦 / 𝑥 ] 𝜑 → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 sb6 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
2 1 biimpri ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → [ 𝑦 / 𝑥 ] 𝜑 )
3 2 axc4i ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 )
4 1 3 sylbi ( [ 𝑦 / 𝑥 ] 𝜑 → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 )