Metamath Proof Explorer


Theorem bj-hbsb2av

Description: Version of hbsb2a with a disjoint variable condition, which does not require ax-13 . (Contributed by BJ, 11-Sep-2019) (Proof modification is discouraged.)

Ref Expression
Assertion bj-hbsb2av ( [ 𝑦 / 𝑥 ] ∀ 𝑦 𝜑 → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 sb4av ( [ 𝑦 / 𝑥 ] ∀ 𝑦 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
2 sb6 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
3 2 biimpri ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → [ 𝑦 / 𝑥 ] 𝜑 )
4 3 axc4i ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 )
5 1 4 syl ( [ 𝑦 / 𝑥 ] ∀ 𝑦 𝜑 → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 )