Metamath Proof Explorer


Theorem bnj219

Description: First-order logic and set theory. (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Assertion bnj219 ( 𝑛 = suc 𝑚 → 𝑚 E 𝑛 )

Proof

Step Hyp Ref Expression
1 vex ⊢ 𝑚 ∈ V
2 1 bnj216 ⊢ ( 𝑛 = suc 𝑚 → 𝑚 ∈ 𝑛 )
3 epel ⊢ ( 𝑚 E 𝑛 ↔ 𝑚 ∈ 𝑛 )
4 2 3 sylibr ⊢ ( 𝑛 = suc 𝑚 → 𝑚 E 𝑛 )