Metamath Proof Explorer


Theorem bnj929

Description: Technical lemma for bnj69 . This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Hypotheses bnj929.1 ( 𝜑 ↔ ( 𝑓 ‘ ∅ ) = pred ( 𝑋 , 𝐴 , 𝑅 ) )
bnj929.4 ( 𝜑′[ 𝑝 / 𝑛 ] 𝜑 )
bnj929.7 ( 𝜑″[ 𝐺 / 𝑓 ] 𝜑′ )
bnj929.10 𝐷 = ( ω ∖ { ∅ } )
bnj929.13 𝐺 = ( 𝑓 ∪ { ⟨ 𝑛 , 𝐶 ⟩ } )
bnj929.50 𝐶 ∈ V
Assertion bnj929 ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) → 𝜑″ )

Proof

Step Hyp Ref Expression
1 bnj929.1 ( 𝜑 ↔ ( 𝑓 ‘ ∅ ) = pred ( 𝑋 , 𝐴 , 𝑅 ) )
2 bnj929.4 ( 𝜑′[ 𝑝 / 𝑛 ] 𝜑 )
3 bnj929.7 ( 𝜑″[ 𝐺 / 𝑓 ] 𝜑′ )
4 bnj929.10 𝐷 = ( ω ∖ { ∅ } )
5 bnj929.13 𝐺 = ( 𝑓 ∪ { ⟨ 𝑛 , 𝐶 ⟩ } )
6 bnj929.50 𝐶 ∈ V
7 bnj645 ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) → 𝜑 )
8 bnj334 ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) ↔ ( 𝑓 Fn 𝑛𝑛𝐷𝑝 = suc 𝑛𝜑 ) )
9 bnj257 ( ( 𝑓 Fn 𝑛𝑛𝐷𝑝 = suc 𝑛𝜑 ) ↔ ( 𝑓 Fn 𝑛𝑛𝐷𝜑𝑝 = suc 𝑛 ) )
10 8 9 bitri ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) ↔ ( 𝑓 Fn 𝑛𝑛𝐷𝜑𝑝 = suc 𝑛 ) )
11 bnj345 ( ( 𝑓 Fn 𝑛𝑛𝐷𝜑𝑝 = suc 𝑛 ) ↔ ( 𝑝 = suc 𝑛𝑓 Fn 𝑛𝑛𝐷𝜑 ) )
12 bnj253 ( ( 𝑝 = suc 𝑛𝑓 Fn 𝑛𝑛𝐷𝜑 ) ↔ ( ( 𝑝 = suc 𝑛𝑓 Fn 𝑛 ) ∧ 𝑛𝐷𝜑 ) )
13 10 11 12 3bitri ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) ↔ ( ( 𝑝 = suc 𝑛𝑓 Fn 𝑛 ) ∧ 𝑛𝐷𝜑 ) )
14 13 simp1bi ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) → ( 𝑝 = suc 𝑛𝑓 Fn 𝑛 ) )
15 5 6 bnj927 ( ( 𝑝 = suc 𝑛𝑓 Fn 𝑛 ) → 𝐺 Fn 𝑝 )
16 15 fnfund ( ( 𝑝 = suc 𝑛𝑓 Fn 𝑛 ) → Fun 𝐺 )
17 14 16 syl ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) → Fun 𝐺 )
18 5 bnj931 𝑓𝐺
19 18 a1i ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) → 𝑓𝐺 )
20 bnj268 ( ( 𝑛𝐷𝑓 Fn 𝑛𝑝 = suc 𝑛𝜑 ) ↔ ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) )
21 bnj253 ( ( 𝑛𝐷𝑓 Fn 𝑛𝑝 = suc 𝑛𝜑 ) ↔ ( ( 𝑛𝐷𝑓 Fn 𝑛 ) ∧ 𝑝 = suc 𝑛𝜑 ) )
22 20 21 bitr3i ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) ↔ ( ( 𝑛𝐷𝑓 Fn 𝑛 ) ∧ 𝑝 = suc 𝑛𝜑 ) )
23 22 simp1bi ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) → ( 𝑛𝐷𝑓 Fn 𝑛 ) )
24 fndm ( 𝑓 Fn 𝑛 → dom 𝑓 = 𝑛 )
25 4 bnj529 ( 𝑛𝐷 → ∅ ∈ 𝑛 )
26 eleq2 ( dom 𝑓 = 𝑛 → ( ∅ ∈ dom 𝑓 ↔ ∅ ∈ 𝑛 ) )
27 26 biimpar ( ( dom 𝑓 = 𝑛 ∧ ∅ ∈ 𝑛 ) → ∅ ∈ dom 𝑓 )
28 24 25 27 syl2anr ( ( 𝑛𝐷𝑓 Fn 𝑛 ) → ∅ ∈ dom 𝑓 )
29 23 28 syl ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) → ∅ ∈ dom 𝑓 )
30 17 19 29 bnj1502 ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) → ( 𝐺 ‘ ∅ ) = ( 𝑓 ‘ ∅ ) )
31 5 bnj918 𝐺 ∈ V
32 1 2 3 31 bnj934 ( ( 𝜑 ∧ ( 𝐺 ‘ ∅ ) = ( 𝑓 ‘ ∅ ) ) → 𝜑″ )
33 7 30 32 syl2anc ( ( 𝑛𝐷𝑝 = suc 𝑛𝑓 Fn 𝑛𝜑 ) → 𝜑″ )