Metamath Proof Explorer


Theorem bracnlnval

Description: The vector that a continuous linear functional is the bra of. (Contributed by NM, 26-May-2006) (New usage is discouraged.)

Ref Expression
Assertion bracnlnval ( 𝑇 ∈ ( LinFn ∩ ContFn ) → 𝑇 = ( bra ‘ ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ) )

Proof

Step Hyp Ref Expression
1 cnvbraval ⊢ ( 𝑇 ∈ ( LinFn ∩ ContFn ) → ( ◡ bra ‘ 𝑇 ) = ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) )
2 cnvbracl ⊢ ( 𝑇 ∈ ( LinFn ∩ ContFn ) → ( ◡ bra ‘ 𝑇 ) ∈ ℋ )
3 1 2 eqeltrrd ⊢ ( 𝑇 ∈ ( LinFn ∩ ContFn ) → ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ∈ ℋ )
4 bra11 ⊢ bra : ℋ –1-1-onto→ ( LinFn ∩ ContFn )
5 f1ocnvfvb ⊢ ( ( bra : ℋ –1-1-onto→ ( LinFn ∩ ContFn ) ∧ ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ∈ ℋ ∧ 𝑇 ∈ ( LinFn ∩ ContFn ) ) → ( ( bra ‘ ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ) = 𝑇 ↔ ( ◡ bra ‘ 𝑇 ) = ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ) )
6 4 5 mp3an1 ⊢ ( ( ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ∈ ℋ ∧ 𝑇 ∈ ( LinFn ∩ ContFn ) ) → ( ( bra ‘ ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ) = 𝑇 ↔ ( ◡ bra ‘ 𝑇 ) = ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ) )
7 3 6 mpancom ⊢ ( 𝑇 ∈ ( LinFn ∩ ContFn ) → ( ( bra ‘ ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ) = 𝑇 ↔ ( ◡ bra ‘ 𝑇 ) = ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ) )
8 1 7 mpbird ⊢ ( 𝑇 ∈ ( LinFn ∩ ContFn ) → ( bra ‘ ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ) = 𝑇 )
9 8 eqcomd ⊢ ( 𝑇 ∈ ( LinFn ∩ ContFn ) → 𝑇 = ( bra ‘ ( ℩ 𝑦 ∈ ℋ ∀ 𝑥 ∈ ℋ ( 𝑇 ‘ 𝑥 ) = ( 𝑥 ·ih 𝑦 ) ) ) )