Theorem brcnvssrid

Description: Any set is a converse subset of itself. (Contributed by Peter Mazsa, 9-Jun-2021)

	Ref	Expression
Assertion	brcnvssrid	⊢ ( 𝐴 ∈ 𝑉 → 𝐴 ◡ S 𝐴 )

Proof

Step	Hyp	Ref	Expression
1		ssid	⊢ 𝐴 ⊆ 𝐴
2		brcnvssr	⊢ ( 𝐴 ∈ 𝑉 → ( 𝐴 ◡ S 𝐴 ↔ 𝐴 ⊆ 𝐴 ) )
3	1 2	mpbiri	⊢ ( 𝐴 ∈ 𝑉 → 𝐴 ◡ S 𝐴 )