Metamath Proof Explorer


Theorem btwnhl2

Description: Deduce half-line from betweenness. (Contributed by Thierry Arnoux, 4-Mar-2020)

Ref Expression
Hypotheses ishlg.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
ishlg.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
ishlg.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
ishlg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
ishlg.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
ishlg.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
hlln.1 ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
hltr.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
btwnhl1.1 ⊢ ( 𝜑 → 𝐶 ∈ ( 𝐴 𝐼 𝐵 ) )
btwnhl1.2 ⊢ ( 𝜑 → 𝐴 ≠ 𝐵 )
btwnhl2.3 ⊢ ( 𝜑 → 𝐶 ≠ 𝐵 )
Assertion btwnhl2 ( 𝜑 → 𝐶 ( 𝐾 ‘ 𝐵 ) 𝐴 )

Proof

Step Hyp Ref Expression
1 ishlg.p ⊢ 𝑃 = ( Base ‘ 𝐺 )
2 ishlg.i ⊢ 𝐼 = ( Itv ‘ 𝐺 )
3 ishlg.k ⊢ 𝐾 = ( hlG ‘ 𝐺 )
4 ishlg.a ⊢ ( 𝜑 → 𝐴 ∈ 𝑃 )
5 ishlg.b ⊢ ( 𝜑 → 𝐵 ∈ 𝑃 )
6 ishlg.c ⊢ ( 𝜑 → 𝐶 ∈ 𝑃 )
7 hlln.1 ⊢ ( 𝜑 → 𝐺 ∈ TarskiG )
8 hltr.d ⊢ ( 𝜑 → 𝐷 ∈ 𝑃 )
9 btwnhl1.1 ⊢ ( 𝜑 → 𝐶 ∈ ( 𝐴 𝐼 𝐵 ) )
10 btwnhl1.2 ⊢ ( 𝜑 → 𝐴 ≠ 𝐵 )
11 btwnhl2.3 ⊢ ( 𝜑 → 𝐶 ≠ 𝐵 )
12 eqid ⊢ ( dist ‘ 𝐺 ) = ( dist ‘ 𝐺 )
13 1 12 2 7 4 6 5 9 tgbtwncom ⊢ ( 𝜑 → 𝐶 ∈ ( 𝐵 𝐼 𝐴 ) )
14 13 orcd ⊢ ( 𝜑 → ( 𝐶 ∈ ( 𝐵 𝐼 𝐴 ) ∨ 𝐴 ∈ ( 𝐵 𝐼 𝐶 ) ) )
15 1 2 3 6 4 5 7 ishlg ⊢ ( 𝜑 → ( 𝐶 ( 𝐾 ‘ 𝐵 ) 𝐴 ↔ ( 𝐶 ≠ 𝐵 ∧ 𝐴 ≠ 𝐵 ∧ ( 𝐶 ∈ ( 𝐵 𝐼 𝐴 ) ∨ 𝐴 ∈ ( 𝐵 𝐼 𝐶 ) ) ) ) )
16 11 10 14 15 mpbir3and ⊢ ( 𝜑 → 𝐶 ( 𝐾 ‘ 𝐵 ) 𝐴 )