Metamath Proof Explorer


Theorem cbvrabv2

Description: A more general version of cbvrabv . Usage of this theorem is discouraged because it depends on ax-13 . Use of cbvrabv2w is preferred. (Contributed by Glauco Siliprandi, 23-Oct-2021) (New usage is discouraged.)

Ref Expression
Hypotheses cbvrabv2.1 ⊢ ( 𝑥 = 𝑦 → 𝐴 = 𝐵 )
cbvrabv2.2 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ 𝜓 ) )
Assertion cbvrabv2 { 𝑥 ∈ 𝐴 ∣ 𝜑 } = { 𝑦 ∈ 𝐵 ∣ 𝜓 }

Proof

Step Hyp Ref Expression
1 cbvrabv2.1 ⊢ ( 𝑥 = 𝑦 → 𝐴 = 𝐵 )
2 cbvrabv2.2 ⊢ ( 𝑥 = 𝑦 → ( 𝜑 ↔ 𝜓 ) )
3 nfcv ⊢ Ⅎ 𝑦 𝐴
4 nfcv ⊢ Ⅎ 𝑥 𝐵
5 nfv ⊢ Ⅎ 𝑦 𝜑
6 nfv ⊢ Ⅎ 𝑥 𝜓
7 3 4 5 6 1 2 cbvrabcsf ⊢ { 𝑥 ∈ 𝐴 ∣ 𝜑 } = { 𝑦 ∈ 𝐵 ∣ 𝜓 }