Metamath Proof Explorer


Theorem ceqsralvOLD

Description: Obsolete version of ceqsalv as of 8-Sep-2024. (Contributed by NM, 21-Jun-2013) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Hypothesis ceqsralv.2 ( 𝑥 = 𝐴 → ( 𝜑𝜓 ) )
Assertion ceqsralvOLD ( 𝐴𝐵 → ( ∀ 𝑥𝐵 ( 𝑥 = 𝐴𝜑 ) ↔ 𝜓 ) )

Proof

Step Hyp Ref Expression
1 ceqsralv.2 ( 𝑥 = 𝐴 → ( 𝜑𝜓 ) )
2 nfv 𝑥 𝜓
3 1 ax-gen 𝑥 ( 𝑥 = 𝐴 → ( 𝜑𝜓 ) )
4 ceqsralt ( ( Ⅎ 𝑥 𝜓 ∧ ∀ 𝑥 ( 𝑥 = 𝐴 → ( 𝜑𝜓 ) ) ∧ 𝐴𝐵 ) → ( ∀ 𝑥𝐵 ( 𝑥 = 𝐴𝜑 ) ↔ 𝜓 ) )
5 2 3 4 mp3an12 ( 𝐴𝐵 → ( ∀ 𝑥𝐵 ( 𝑥 = 𝐴𝜑 ) ↔ 𝜓 ) )