Metamath Proof Explorer


Theorem cicpropd

Description: Two structures with the same base, hom-sets and composition operation have the same isomorphic objects. (Contributed by Zhi Wang, 27-Oct-2025)

Ref Expression
Hypotheses cicpropd.1 ⊢ ( 𝜑 → ( Homf ‘ 𝐶 ) = ( Homf ‘ 𝐷 ) )
cicpropd.2 ⊢ ( 𝜑 → ( compf ‘ 𝐶 ) = ( compf ‘ 𝐷 ) )
Assertion cicpropd ( 𝜑 → ( ≃𝑐 ‘ 𝐶 ) = ( ≃𝑐 ‘ 𝐷 ) )

Proof

Step Hyp Ref Expression
1 cicpropd.1 ⊢ ( 𝜑 → ( Homf ‘ 𝐶 ) = ( Homf ‘ 𝐷 ) )
2 cicpropd.2 ⊢ ( 𝜑 → ( compf ‘ 𝐶 ) = ( compf ‘ 𝐷 ) )
3 1 2 cicpropdlem ⊢ ( ( 𝜑 ∧ 𝑓 ∈ ( ≃𝑐 ‘ 𝐶 ) ) → 𝑓 ∈ ( ≃𝑐 ‘ 𝐷 ) )
4 1 eqcomd ⊢ ( 𝜑 → ( Homf ‘ 𝐷 ) = ( Homf ‘ 𝐶 ) )
5 2 eqcomd ⊢ ( 𝜑 → ( compf ‘ 𝐷 ) = ( compf ‘ 𝐶 ) )
6 4 5 cicpropdlem ⊢ ( ( 𝜑 ∧ 𝑓 ∈ ( ≃𝑐 ‘ 𝐷 ) ) → 𝑓 ∈ ( ≃𝑐 ‘ 𝐶 ) )
7 3 6 impbida ⊢ ( 𝜑 → ( 𝑓 ∈ ( ≃𝑐 ‘ 𝐶 ) ↔ 𝑓 ∈ ( ≃𝑐 ‘ 𝐷 ) ) )
8 7 eqrdv ⊢ ( 𝜑 → ( ≃𝑐 ‘ 𝐶 ) = ( ≃𝑐 ‘ 𝐷 ) )