Metamath Proof Explorer
		
		
		
		Description:  A number is nonzero iff its complex conjugate is nonzero.
         (Contributed by Mario Carneiro, 29-May-2016)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | recld.1 | ⊢ ( 𝜑  →  𝐴  ∈  ℂ ) | 
					
						|  |  | cjne0d.2 | ⊢ ( 𝜑  →  𝐴  ≠  0 ) | 
				
					|  | Assertion | cjne0d | ⊢  ( 𝜑  →  ( ∗ ‘ 𝐴 )  ≠  0 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | recld.1 | ⊢ ( 𝜑  →  𝐴  ∈  ℂ ) | 
						
							| 2 |  | cjne0d.2 | ⊢ ( 𝜑  →  𝐴  ≠  0 ) | 
						
							| 3 |  | cjne0 | ⊢ ( 𝐴  ∈  ℂ  →  ( 𝐴  ≠  0  ↔  ( ∗ ‘ 𝐴 )  ≠  0 ) ) | 
						
							| 4 | 1 3 | syl | ⊢ ( 𝜑  →  ( 𝐴  ≠  0  ↔  ( ∗ ‘ 𝐴 )  ≠  0 ) ) | 
						
							| 5 | 2 4 | mpbid | ⊢ ( 𝜑  →  ( ∗ ‘ 𝐴 )  ≠  0 ) |