Metamath Proof Explorer


Theorem clatglble

Description: The greatest lower bound is the least element. (Contributed by NM, 5-Dec-2011)

Ref Expression
Hypotheses clatglb.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
clatglb.l ⊢ ≤ = ( le ‘ 𝐾 )
clatglb.g ⊢ 𝐺 = ( glb ‘ 𝐾 )
Assertion clatglble ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ∧ 𝑋 ∈ 𝑆 ) → ( 𝐺 ‘ 𝑆 ) ≤ 𝑋 )

Proof

Step Hyp Ref Expression
1 clatglb.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
2 clatglb.l ⊢ ≤ = ( le ‘ 𝐾 )
3 clatglb.g ⊢ 𝐺 = ( glb ‘ 𝐾 )
4 simp1 ⊢ ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ∧ 𝑋 ∈ 𝑆 ) → 𝐾 ∈ CLat )
5 1 3 clatglbcl2 ⊢ ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ) → 𝑆 ∈ dom 𝐺 )
6 5 3adant3 ⊢ ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ∧ 𝑋 ∈ 𝑆 ) → 𝑆 ∈ dom 𝐺 )
7 simp3 ⊢ ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ∧ 𝑋 ∈ 𝑆 ) → 𝑋 ∈ 𝑆 )
8 1 2 3 4 6 7 glble ⊢ ( ( 𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵 ∧ 𝑋 ∈ 𝑆 ) → ( 𝐺 ‘ 𝑆 ) ≤ 𝑋 )