Metamath Proof Explorer


Theorem clelsb1f

Description: Substitution for the first argument of the membership predicate in an atomic formula (class version of elsb1 ). Usage of this theorem is discouraged because it depends on ax-13 . See clelsb1fw not requiring ax-13 , but extra disjoint variables. (Contributed by Rodolfo Medina, 28-Apr-2010) (Proof shortened by Andrew Salmon, 14-Jun-2011) (Revised by Thierry Arnoux, 13-Mar-2017) (Proof shortened by Wolf Lammen, 7-May-2023) (New usage is discouraged.)

Ref Expression
Hypothesis clelsb1f.1 𝑥 𝐴
Assertion clelsb1f ( [ 𝑦 / 𝑥 ] 𝑥𝐴𝑦𝐴 )

Proof

Step Hyp Ref Expression
1 clelsb1f.1 𝑥 𝐴
2 1 nfcri 𝑥 𝑤𝐴
3 2 sbco2 ( [ 𝑦 / 𝑥 ] [ 𝑥 / 𝑤 ] 𝑤𝐴 ↔ [ 𝑦 / 𝑤 ] 𝑤𝐴 )
4 clelsb1 ( [ 𝑥 / 𝑤 ] 𝑤𝐴𝑥𝐴 )
5 4 sbbii ( [ 𝑦 / 𝑥 ] [ 𝑥 / 𝑤 ] 𝑤𝐴 ↔ [ 𝑦 / 𝑥 ] 𝑥𝐴 )
6 clelsb1 ( [ 𝑦 / 𝑤 ] 𝑤𝐴𝑦𝐴 )
7 3 5 6 3bitr3i ( [ 𝑦 / 𝑥 ] 𝑥𝐴𝑦𝐴 )