Metamath Proof Explorer


Theorem clnbgr0vtx

Description: In a null graph (with no vertices), all closed neighborhoods are empty. (Contributed by AV, 15-Nov-2020)

Ref Expression
Assertion clnbgr0vtx ( ( Vtx ‘ 𝐺 ) = ∅ → ( 𝐺 ClNeighbVtx 𝐾 ) = ∅ )

Proof

Step Hyp Ref Expression
1 nel02 ( ( Vtx ‘ 𝐺 ) = ∅ → ¬ 𝐾 ∈ ( Vtx ‘ 𝐺 ) )
2 df-nel ( 𝐾 ∉ ( Vtx ‘ 𝐺 ) ↔ ¬ 𝐾 ∈ ( Vtx ‘ 𝐺 ) )
3 1 2 sylibr ( ( Vtx ‘ 𝐺 ) = ∅ → 𝐾 ∉ ( Vtx ‘ 𝐺 ) )
4 eqid ( Vtx ‘ 𝐺 ) = ( Vtx ‘ 𝐺 )
5 4 clnbgrnvtx0 ( 𝐾 ∉ ( Vtx ‘ 𝐺 ) → ( 𝐺 ClNeighbVtx 𝐾 ) = ∅ )
6 3 5 syl ( ( Vtx ‘ 𝐺 ) = ∅ → ( 𝐺 ClNeighbVtx 𝐾 ) = ∅ )