Metamath Proof Explorer


Theorem cnveqb

Description: Equality theorem for converse. (Contributed by FL, 19-Sep-2011)

Ref Expression
Assertion cnveqb ( ( Rel 𝐴 ∧ Rel 𝐵 ) → ( 𝐴 = 𝐵 ↔ ◡ 𝐴 = ◡ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 cnvssb ⊢ ( Rel 𝐴 → ( 𝐴 ⊆ 𝐵 ↔ ◡ 𝐴 ⊆ ◡ 𝐵 ) )
2 cnvssb ⊢ ( Rel 𝐵 → ( 𝐵 ⊆ 𝐴 ↔ ◡ 𝐵 ⊆ ◡ 𝐴 ) )
3 1 2 bi2anan9 ⊢ ( ( Rel 𝐴 ∧ Rel 𝐵 ) → ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴 ) ↔ ( ◡ 𝐴 ⊆ ◡ 𝐵 ∧ ◡ 𝐵 ⊆ ◡ 𝐴 ) ) )
4 eqss ⊢ ( 𝐴 = 𝐵 ↔ ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴 ) )
5 eqss ⊢ ( ◡ 𝐴 = ◡ 𝐵 ↔ ( ◡ 𝐴 ⊆ ◡ 𝐵 ∧ ◡ 𝐵 ⊆ ◡ 𝐴 ) )
6 3 4 5 3bitr4g ⊢ ( ( Rel 𝐴 ∧ Rel 𝐵 ) → ( 𝐴 = 𝐵 ↔ ◡ 𝐴 = ◡ 𝐵 ) )