Metamath Proof Explorer


Theorem cnveqd

Description: Equality deduction for converse relation. (Contributed by NM, 6-Dec-2013)

Ref Expression
Hypothesis cnveqd.1 ( 𝜑𝐴 = 𝐵 )
Assertion cnveqd ( 𝜑 𝐴 = 𝐵 )

Proof

Step Hyp Ref Expression
1 cnveqd.1 ( 𝜑𝐴 = 𝐵 )
2 cnveq ( 𝐴 = 𝐵 𝐴 = 𝐵 )
3 1 2 syl ( 𝜑 𝐴 = 𝐵 )