Metamath Proof Explorer
Description: Equality inference for composition of two classes. (Contributed by FL, 7-Jun-2012)
|
|
Ref |
Expression |
|
Hypotheses |
coeq12i.1 |
⊢ 𝐴 = 𝐵 |
|
|
coeq12i.2 |
⊢ 𝐶 = 𝐷 |
|
Assertion |
coeq12i |
⊢ ( 𝐴 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐷 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
coeq12i.1 |
⊢ 𝐴 = 𝐵 |
2 |
|
coeq12i.2 |
⊢ 𝐶 = 𝐷 |
3 |
1
|
coeq1i |
⊢ ( 𝐴 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐶 ) |
4 |
2
|
coeq2i |
⊢ ( 𝐵 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐷 ) |
5 |
3 4
|
eqtri |
⊢ ( 𝐴 ∘ 𝐶 ) = ( 𝐵 ∘ 𝐷 ) |