Metamath Proof Explorer


Theorem cofcut1d

Description: If C is cofinal with A and D is coinitial with B and the cut of A and B lies between C and D , then the cut of C and D is equal to the cut of A and B . Theorem 2.6 of Gonshor p. 10. (Contributed by Scott Fenton, 23-Jan-2025)

Ref Expression
Hypotheses cofcut1d.1 ( 𝜑𝐴 <<s 𝐵 )
cofcut1d.2 ( 𝜑 → ∀ 𝑥𝐴𝑦𝐶 𝑥 ≤s 𝑦 )
cofcut1d.3 ( 𝜑 → ∀ 𝑧𝐵𝑤𝐷 𝑤 ≤s 𝑧 )
cofcut1d.4 ( 𝜑𝐶 <<s { ( 𝐴 |s 𝐵 ) } )
cofcut1d.5 ( 𝜑 → { ( 𝐴 |s 𝐵 ) } <<s 𝐷 )
Assertion cofcut1d ( 𝜑 → ( 𝐴 |s 𝐵 ) = ( 𝐶 |s 𝐷 ) )

Proof

Step Hyp Ref Expression
1 cofcut1d.1 ( 𝜑𝐴 <<s 𝐵 )
2 cofcut1d.2 ( 𝜑 → ∀ 𝑥𝐴𝑦𝐶 𝑥 ≤s 𝑦 )
3 cofcut1d.3 ( 𝜑 → ∀ 𝑧𝐵𝑤𝐷 𝑤 ≤s 𝑧 )
4 cofcut1d.4 ( 𝜑𝐶 <<s { ( 𝐴 |s 𝐵 ) } )
5 cofcut1d.5 ( 𝜑 → { ( 𝐴 |s 𝐵 ) } <<s 𝐷 )
6 cofcut1 ( ( 𝐴 <<s 𝐵 ∧ ( ∀ 𝑥𝐴𝑦𝐶 𝑥 ≤s 𝑦 ∧ ∀ 𝑧𝐵𝑤𝐷 𝑤 ≤s 𝑧 ) ∧ ( 𝐶 <<s { ( 𝐴 |s 𝐵 ) } ∧ { ( 𝐴 |s 𝐵 ) } <<s 𝐷 ) ) → ( 𝐴 |s 𝐵 ) = ( 𝐶 |s 𝐷 ) )
7 1 2 3 4 5 6 syl122anc ( 𝜑 → ( 𝐴 |s 𝐵 ) = ( 𝐶 |s 𝐷 ) )