| Step | 
						Hyp | 
						Ref | 
						Expression | 
					
						
							| 1 | 
							
								
							 | 
							cofuval.b | 
							⊢ 𝐵  =  ( Base ‘ 𝐶 )  | 
						
						
							| 2 | 
							
								
							 | 
							cofuval.f | 
							⊢ ( 𝜑  →  𝐹  ∈  ( 𝐶  Func  𝐷 ) )  | 
						
						
							| 3 | 
							
								
							 | 
							cofuval.g | 
							⊢ ( 𝜑  →  𝐺  ∈  ( 𝐷  Func  𝐸 ) )  | 
						
						
							| 4 | 
							
								
							 | 
							cofu2nd.x | 
							⊢ ( 𝜑  →  𝑋  ∈  𝐵 )  | 
						
						
							| 5 | 
							
								1 2 3
							 | 
							cofu1st | 
							⊢ ( 𝜑  →  ( 1st  ‘ ( 𝐺  ∘func  𝐹 ) )  =  ( ( 1st  ‘ 𝐺 )  ∘  ( 1st  ‘ 𝐹 ) ) )  | 
						
						
							| 6 | 
							
								5
							 | 
							fveq1d | 
							⊢ ( 𝜑  →  ( ( 1st  ‘ ( 𝐺  ∘func  𝐹 ) ) ‘ 𝑋 )  =  ( ( ( 1st  ‘ 𝐺 )  ∘  ( 1st  ‘ 𝐹 ) ) ‘ 𝑋 ) )  | 
						
						
							| 7 | 
							
								
							 | 
							eqid | 
							⊢ ( Base ‘ 𝐷 )  =  ( Base ‘ 𝐷 )  | 
						
						
							| 8 | 
							
								
							 | 
							relfunc | 
							⊢ Rel  ( 𝐶  Func  𝐷 )  | 
						
						
							| 9 | 
							
								
							 | 
							1st2ndbr | 
							⊢ ( ( Rel  ( 𝐶  Func  𝐷 )  ∧  𝐹  ∈  ( 𝐶  Func  𝐷 ) )  →  ( 1st  ‘ 𝐹 ) ( 𝐶  Func  𝐷 ) ( 2nd  ‘ 𝐹 ) )  | 
						
						
							| 10 | 
							
								8 2 9
							 | 
							sylancr | 
							⊢ ( 𝜑  →  ( 1st  ‘ 𝐹 ) ( 𝐶  Func  𝐷 ) ( 2nd  ‘ 𝐹 ) )  | 
						
						
							| 11 | 
							
								1 7 10
							 | 
							funcf1 | 
							⊢ ( 𝜑  →  ( 1st  ‘ 𝐹 ) : 𝐵 ⟶ ( Base ‘ 𝐷 ) )  | 
						
						
							| 12 | 
							
								
							 | 
							fvco3 | 
							⊢ ( ( ( 1st  ‘ 𝐹 ) : 𝐵 ⟶ ( Base ‘ 𝐷 )  ∧  𝑋  ∈  𝐵 )  →  ( ( ( 1st  ‘ 𝐺 )  ∘  ( 1st  ‘ 𝐹 ) ) ‘ 𝑋 )  =  ( ( 1st  ‘ 𝐺 ) ‘ ( ( 1st  ‘ 𝐹 ) ‘ 𝑋 ) ) )  | 
						
						
							| 13 | 
							
								11 4 12
							 | 
							syl2anc | 
							⊢ ( 𝜑  →  ( ( ( 1st  ‘ 𝐺 )  ∘  ( 1st  ‘ 𝐹 ) ) ‘ 𝑋 )  =  ( ( 1st  ‘ 𝐺 ) ‘ ( ( 1st  ‘ 𝐹 ) ‘ 𝑋 ) ) )  | 
						
						
							| 14 | 
							
								6 13
							 | 
							eqtrd | 
							⊢ ( 𝜑  →  ( ( 1st  ‘ ( 𝐺  ∘func  𝐹 ) ) ‘ 𝑋 )  =  ( ( 1st  ‘ 𝐺 ) ‘ ( ( 1st  ‘ 𝐹 ) ‘ 𝑋 ) ) )  |