Metamath Proof Explorer
		
		
		
		Description:  Commutation of antecedents.  Swap 1st and 5th.  (Contributed by Jeff
       Hankins, 28-Jun-2009)  (Proof shortened by Wolf Lammen, 29-Jul-2012)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypothesis | com5.1 | ⊢ ( 𝜑  →  ( 𝜓  →  ( 𝜒  →  ( 𝜃  →  ( 𝜏  →  𝜂 ) ) ) ) ) | 
				
					|  | Assertion | com15 | ⊢  ( 𝜏  →  ( 𝜓  →  ( 𝜒  →  ( 𝜃  →  ( 𝜑  →  𝜂 ) ) ) ) ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | com5.1 | ⊢ ( 𝜑  →  ( 𝜓  →  ( 𝜒  →  ( 𝜃  →  ( 𝜏  →  𝜂 ) ) ) ) ) | 
						
							| 2 | 1 | com5l | ⊢ ( 𝜓  →  ( 𝜒  →  ( 𝜃  →  ( 𝜏  →  ( 𝜑  →  𝜂 ) ) ) ) ) | 
						
							| 3 | 2 | com4r | ⊢ ( 𝜏  →  ( 𝜓  →  ( 𝜒  →  ( 𝜃  →  ( 𝜑  →  𝜂 ) ) ) ) ) |