Metamath Proof Explorer


Theorem conncompconn

Description: The connected component containing A is connected. (Contributed by Mario Carneiro, 19-Mar-2015)

Ref Expression
Hypothesis conncomp.2 𝑆 = { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) }
Assertion conncompconn ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) → ( 𝐽t 𝑆 ) ∈ Conn )

Proof

Step Hyp Ref Expression
1 conncomp.2 𝑆 = { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) }
2 uniiun { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } = 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } 𝑦
3 1 2 eqtri 𝑆 = 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } 𝑦
4 3 oveq2i ( 𝐽t 𝑆 ) = ( 𝐽t 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } 𝑦 )
5 simpl ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) → 𝐽 ∈ ( TopOn ‘ 𝑋 ) )
6 eleq2w ( 𝑥 = 𝑦 → ( 𝐴𝑥𝐴𝑦 ) )
7 oveq2 ( 𝑥 = 𝑦 → ( 𝐽t 𝑥 ) = ( 𝐽t 𝑦 ) )
8 7 eleq1d ( 𝑥 = 𝑦 → ( ( 𝐽t 𝑥 ) ∈ Conn ↔ ( 𝐽t 𝑦 ) ∈ Conn ) )
9 6 8 anbi12d ( 𝑥 = 𝑦 → ( ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) ↔ ( 𝐴𝑦 ∧ ( 𝐽t 𝑦 ) ∈ Conn ) ) )
10 9 elrab ( 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } ↔ ( 𝑦 ∈ 𝒫 𝑋 ∧ ( 𝐴𝑦 ∧ ( 𝐽t 𝑦 ) ∈ Conn ) ) )
11 10 bilani ( ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) ∧ 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } ) → ( 𝑦 ∈ 𝒫 𝑋 ∧ ( 𝐴𝑦 ∧ ( 𝐽t 𝑦 ) ∈ Conn ) ) )
12 11 simpld ( ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) ∧ 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } ) → 𝑦 ∈ 𝒫 𝑋 )
13 12 elpwid ( ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) ∧ 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } ) → 𝑦𝑋 )
14 11 simprd ( ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) ∧ 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } ) → ( 𝐴𝑦 ∧ ( 𝐽t 𝑦 ) ∈ Conn ) )
15 14 simpld ( ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) ∧ 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } ) → 𝐴𝑦 )
16 14 simprd ( ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) ∧ 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } ) → ( 𝐽t 𝑦 ) ∈ Conn )
17 5 13 15 16 iunconn ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) → ( 𝐽t 𝑦 ∈ { 𝑥 ∈ 𝒫 𝑋 ∣ ( 𝐴𝑥 ∧ ( 𝐽t 𝑥 ) ∈ Conn ) } 𝑦 ) ∈ Conn )
18 4 17 eqeltrid ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝐴𝑋 ) → ( 𝐽t 𝑆 ) ∈ Conn )