Metamath Proof Explorer


Theorem constrabscl

Description: Constructible numbers are closed under absolute value (modulus). (Contributed by Thierry Arnoux, 6-Nov-2025)

Ref Expression
Hypothesis constrabscl.1 ⊢ ( 𝜑 → 𝑋 ∈ Constr )
Assertion constrabscl ( 𝜑 → ( abs ‘ 𝑋 ) ∈ Constr )

Proof

Step Hyp Ref Expression
1 constrabscl.1 ⊢ ( 𝜑 → 𝑋 ∈ Constr )
2 0zd ⊢ ( 𝜑 → 0 ∈ ℤ )
3 2 zconstr ⊢ ( 𝜑 → 0 ∈ Constr )
4 1zzd ⊢ ( 𝜑 → 1 ∈ ℤ )
5 4 zconstr ⊢ ( 𝜑 → 1 ∈ Constr )
6 1 constrcn ⊢ ( 𝜑 → 𝑋 ∈ ℂ )
7 6 abscld ⊢ ( 𝜑 → ( abs ‘ 𝑋 ) ∈ ℝ )
8 7 recnd ⊢ ( 𝜑 → ( abs ‘ 𝑋 ) ∈ ℂ )
9 1m0e1 ⊢ ( 1 − 0 ) = 1
10 9 a1i ⊢ ( 𝜑 → ( 1 − 0 ) = 1 )
11 ax-1cn ⊢ 1 ∈ ℂ
12 10 11 eqeltrdi ⊢ ( 𝜑 → ( 1 − 0 ) ∈ ℂ )
13 8 12 mulcld ⊢ ( 𝜑 → ( ( abs ‘ 𝑋 ) · ( 1 − 0 ) ) ∈ ℂ )
14 13 addlidd ⊢ ( 𝜑 → ( 0 + ( ( abs ‘ 𝑋 ) · ( 1 − 0 ) ) ) = ( ( abs ‘ 𝑋 ) · ( 1 − 0 ) ) )
15 10 oveq2d ⊢ ( 𝜑 → ( ( abs ‘ 𝑋 ) · ( 1 − 0 ) ) = ( ( abs ‘ 𝑋 ) · 1 ) )
16 8 mulridd ⊢ ( 𝜑 → ( ( abs ‘ 𝑋 ) · 1 ) = ( abs ‘ 𝑋 ) )
17 14 15 16 3eqtrrd ⊢ ( 𝜑 → ( abs ‘ 𝑋 ) = ( 0 + ( ( abs ‘ 𝑋 ) · ( 1 − 0 ) ) ) )
18 6 absge0d ⊢ ( 𝜑 → 0 ≤ ( abs ‘ 𝑋 ) )
19 7 18 absidd ⊢ ( 𝜑 → ( abs ‘ ( abs ‘ 𝑋 ) ) = ( abs ‘ 𝑋 ) )
20 8 subid1d ⊢ ( 𝜑 → ( ( abs ‘ 𝑋 ) − 0 ) = ( abs ‘ 𝑋 ) )
21 20 fveq2d ⊢ ( 𝜑 → ( abs ‘ ( ( abs ‘ 𝑋 ) − 0 ) ) = ( abs ‘ ( abs ‘ 𝑋 ) ) )
22 6 subid1d ⊢ ( 𝜑 → ( 𝑋 − 0 ) = 𝑋 )
23 22 fveq2d ⊢ ( 𝜑 → ( abs ‘ ( 𝑋 − 0 ) ) = ( abs ‘ 𝑋 ) )
24 19 21 23 3eqtr4d ⊢ ( 𝜑 → ( abs ‘ ( ( abs ‘ 𝑋 ) − 0 ) ) = ( abs ‘ ( 𝑋 − 0 ) ) )
25 3 5 3 1 3 7 8 17 24 constrlccl ⊢ ( 𝜑 → ( abs ‘ 𝑋 ) ∈ Constr )