Metamath Proof Explorer
		
		
		
		Description:  A proof by contradiction, in deduction form.  (Contributed by Giovanni
       Mascellani, 19-Mar-2018)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | contrd.1 | ⊢ ( 𝜑  →  ( ¬  𝜓  →  𝜒 ) ) | 
					
						|  |  | contrd.2 | ⊢ ( 𝜑  →  ( ¬  𝜓  →  ¬  𝜒 ) ) | 
				
					|  | Assertion | contrd | ⊢  ( 𝜑  →  𝜓 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | contrd.1 | ⊢ ( 𝜑  →  ( ¬  𝜓  →  𝜒 ) ) | 
						
							| 2 |  | contrd.2 | ⊢ ( 𝜑  →  ( ¬  𝜓  →  ¬  𝜒 ) ) | 
						
							| 3 | 1 2 | jcad | ⊢ ( 𝜑  →  ( ¬  𝜓  →  ( 𝜒  ∧  ¬  𝜒 ) ) ) | 
						
							| 4 |  | pm2.24 | ⊢ ( 𝜒  →  ( ¬  𝜒  →  𝜓 ) ) | 
						
							| 5 | 4 | imp | ⊢ ( ( 𝜒  ∧  ¬  𝜒 )  →  𝜓 ) | 
						
							| 6 | 5 | imim2i | ⊢ ( ( ¬  𝜓  →  ( 𝜒  ∧  ¬  𝜒 ) )  →  ( ¬  𝜓  →  𝜓 ) ) | 
						
							| 7 | 6 | pm2.18d | ⊢ ( ( ¬  𝜓  →  ( 𝜒  ∧  ¬  𝜒 ) )  →  𝜓 ) | 
						
							| 8 | 3 7 | syl | ⊢ ( 𝜑  →  𝜓 ) |