Metamath Proof Explorer


Theorem csbeq2d

Description: Formula-building deduction for class substitution. (Contributed by NM, 22-Nov-2005) (Revised by Mario Carneiro, 1-Sep-2015)

Ref Expression
Hypotheses csbeq2d.1 ⊢ Ⅎ 𝑥 𝜑
csbeq2d.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
Assertion csbeq2d ( 𝜑 → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = ⦋ 𝐴 / 𝑥 ⦌ 𝐶 )

Proof

Step Hyp Ref Expression
1 csbeq2d.1 ⊢ Ⅎ 𝑥 𝜑
2 csbeq2d.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
3 2 eleq2d ⊢ ( 𝜑 → ( 𝑦 ∈ 𝐵 ↔ 𝑦 ∈ 𝐶 ) )
4 1 3 sbcbid ⊢ ( 𝜑 → ( [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 ↔ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐶 ) )
5 4 abbidv ⊢ ( 𝜑 → { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 } = { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐶 } )
6 df-csb ⊢ ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐵 }
7 df-csb ⊢ ⦋ 𝐴 / 𝑥 ⦌ 𝐶 = { 𝑦 ∣ [ 𝐴 / 𝑥 ] 𝑦 ∈ 𝐶 }
8 5 6 7 3eqtr4g ⊢ ( 𝜑 → ⦋ 𝐴 / 𝑥 ⦌ 𝐵 = ⦋ 𝐴 / 𝑥 ⦌ 𝐶 )