Metamath Proof Explorer


Theorem csbuni

Description: Distribute proper substitution through the union of a class. (Contributed by Alan Sare, 10-Nov-2012) (Revised by NM, 22-Aug-2018)

Ref Expression
Assertion csbuni 𝐴 / 𝑥 𝐵 = 𝐴 / 𝑥 𝐵

Proof

Step Hyp Ref Expression
1 csbab 𝐴 / 𝑥 { 𝑧 ∣ ∃ 𝑦 ( 𝑧𝑦𝑦𝐵 ) } = { 𝑧[ 𝐴 / 𝑥 ]𝑦 ( 𝑧𝑦𝑦𝐵 ) }
2 sbcex2 ( [ 𝐴 / 𝑥 ]𝑦 ( 𝑧𝑦𝑦𝐵 ) ↔ ∃ 𝑦 [ 𝐴 / 𝑥 ] ( 𝑧𝑦𝑦𝐵 ) )
3 sbcan ( [ 𝐴 / 𝑥 ] ( 𝑧𝑦𝑦𝐵 ) ↔ ( [ 𝐴 / 𝑥 ] 𝑧𝑦[ 𝐴 / 𝑥 ] 𝑦𝐵 ) )
4 sbcg ( 𝐴 ∈ V → ( [ 𝐴 / 𝑥 ] 𝑧𝑦𝑧𝑦 ) )
5 4 anbi1d ( 𝐴 ∈ V → ( ( [ 𝐴 / 𝑥 ] 𝑧𝑦[ 𝐴 / 𝑥 ] 𝑦𝐵 ) ↔ ( 𝑧𝑦[ 𝐴 / 𝑥 ] 𝑦𝐵 ) ) )
6 sbcel2 ( [ 𝐴 / 𝑥 ] 𝑦𝐵𝑦 𝐴 / 𝑥 𝐵 )
7 6 anbi2i ( ( 𝑧𝑦[ 𝐴 / 𝑥 ] 𝑦𝐵 ) ↔ ( 𝑧𝑦𝑦 𝐴 / 𝑥 𝐵 ) )
8 5 7 bitrdi ( 𝐴 ∈ V → ( ( [ 𝐴 / 𝑥 ] 𝑧𝑦[ 𝐴 / 𝑥 ] 𝑦𝐵 ) ↔ ( 𝑧𝑦𝑦 𝐴 / 𝑥 𝐵 ) ) )
9 3 8 syl5bb ( 𝐴 ∈ V → ( [ 𝐴 / 𝑥 ] ( 𝑧𝑦𝑦𝐵 ) ↔ ( 𝑧𝑦𝑦 𝐴 / 𝑥 𝐵 ) ) )
10 9 exbidv ( 𝐴 ∈ V → ( ∃ 𝑦 [ 𝐴 / 𝑥 ] ( 𝑧𝑦𝑦𝐵 ) ↔ ∃ 𝑦 ( 𝑧𝑦𝑦 𝐴 / 𝑥 𝐵 ) ) )
11 2 10 syl5bb ( 𝐴 ∈ V → ( [ 𝐴 / 𝑥 ]𝑦 ( 𝑧𝑦𝑦𝐵 ) ↔ ∃ 𝑦 ( 𝑧𝑦𝑦 𝐴 / 𝑥 𝐵 ) ) )
12 11 abbidv ( 𝐴 ∈ V → { 𝑧[ 𝐴 / 𝑥 ]𝑦 ( 𝑧𝑦𝑦𝐵 ) } = { 𝑧 ∣ ∃ 𝑦 ( 𝑧𝑦𝑦 𝐴 / 𝑥 𝐵 ) } )
13 1 12 syl5eq ( 𝐴 ∈ V → 𝐴 / 𝑥 { 𝑧 ∣ ∃ 𝑦 ( 𝑧𝑦𝑦𝐵 ) } = { 𝑧 ∣ ∃ 𝑦 ( 𝑧𝑦𝑦 𝐴 / 𝑥 𝐵 ) } )
14 df-uni 𝐵 = { 𝑧 ∣ ∃ 𝑦 ( 𝑧𝑦𝑦𝐵 ) }
15 14 csbeq2i 𝐴 / 𝑥 𝐵 = 𝐴 / 𝑥 { 𝑧 ∣ ∃ 𝑦 ( 𝑧𝑦𝑦𝐵 ) }
16 df-uni 𝐴 / 𝑥 𝐵 = { 𝑧 ∣ ∃ 𝑦 ( 𝑧𝑦𝑦 𝐴 / 𝑥 𝐵 ) }
17 13 15 16 3eqtr4g ( 𝐴 ∈ V → 𝐴 / 𝑥 𝐵 = 𝐴 / 𝑥 𝐵 )
18 csbprc ( ¬ 𝐴 ∈ V → 𝐴 / 𝑥 𝐵 = ∅ )
19 csbprc ( ¬ 𝐴 ∈ V → 𝐴 / 𝑥 𝐵 = ∅ )
20 19 unieqd ( ¬ 𝐴 ∈ V → 𝐴 / 𝑥 𝐵 = ∅ )
21 uni0 ∅ = ∅
22 20 21 eqtr2di ( ¬ 𝐴 ∈ V → ∅ = 𝐴 / 𝑥 𝐵 )
23 18 22 eqtrd ( ¬ 𝐴 ∈ V → 𝐴 / 𝑥 𝐵 = 𝐴 / 𝑥 𝐵 )
24 17 23 pm2.61i 𝐴 / 𝑥 𝐵 = 𝐴 / 𝑥 𝐵